NTA has declared the Tie-Breaking Rule and Eligibility of foreign students. Certificates used in the Application form must be updated one.
This Year, IIT Delhi will be going to conduct the JEE Advanced examination on 17 May 2020. This exam will lead to the admission of students in the 23 IITs across the country and the number of seats is 12463. There will be two sessions in the exam and their timing will be 9:00 am to 12:00 am and 2:30 pm to 5:30 pm respectively.
There are several frequently asked questions (FAQs) related JEE Advanced have been released. With the JEE Main result, approx. 245000 students are going to be selected as eligible candidates till 30 April for JEE Advanced Exam. Later, it was also mentioned in time-table that the expected date of JEE Advanced exam result is 8 June.
As per the reports, 174432 students have been applied for JEE Advanced exam last year and the students that have appeared in the exam are 161319. As per the FAQs generally asked by the students for the online Application form, the submission of respective documents for the students of OBC and EWS category is important after April 1 2020.
In case, if the certificate is not available till the last date of the application then the student can only apply as general category candidate. In addition to this, there is the advantage of an extra hour during JEE Advanced for the student who belongs to the disability category.
Criteria for Foreign Candidate Eligibility
At the time of registering of JEE Advanced, Foreign Candidates must:
- Not be citizens of India (by birth or any other reason)
- Have studied (or studying) abroad at 10+2 level or equivalent
There are supernumerary seats allotted to the candidates with a cap of 10% in every course during the admission.
As per the rules of category mandated by Govt. of India, Foreign Nationals are outside the scope of reservation of seats as like Gen-EWS, OBC-EWS, etc. These candidates are allowed to give directly JEE Advanced 2020 with proper eligibility without appearing for JEE Main 2020.
JEE’s Tie Breaking Rule
This rule is applied for case: If two students have equal aggregate marks in JEE Advanced 2020, the rule is applied to distinguish the rank:
Rule 1: Firstly the positive marks of the candidates will be considered and higher rank will be given to the candidate having higher positive marks. In case, if it fails then another rule be followed given in next para.
Rule 2: Higher rank will be given to candidate having better marks in major subject, i.e. mathematics. Even if, this rule is not able to break the tie, then their physics marks are considered. Whoever students have higher marks in physics will get a higher rank. Even if, the tie did not break then the candidates will get the same rank.
Important: Join Matrix Online Test of Series (Most) for JEE Main and Advanced 2020 along with some Free Mock Test & Sample Papers
One more chance for students who withdrew seats in JoSAA 2019 Counselling
Many students who paid the acceptance fee during JoSAA Counselling last year and were unable to report at the allotted centre. These students have withdrawn their seats before the final round and now they are eligible for the JEE Advanced 2020. In addition to this, students who are in NIT can also eligible for the JEE Advanced 2020.
Benefit for Students Applying for Marks Improvement
If a candidate wants to improve its marks in any of the relevant subjects after passing his\her Class XII (or equivalent) in order to meet the criteria “aggregate marks of 75% in JEE (or 65% for SC, ST and PwD)”, then he/she can reappear in any number of subjects in which improvement is considered. In such a case, final marks will be considered for the marks obtained in either of the two attempts of 2019 or 2020.
Check here full JEE Advanced 2020 FAQ’s !
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