JEE Main exam pattern 2019 was announced by NTA. The exam is spread over two papers – Paper 1 and Paper 2. While JEE Main 2019 Paper 1 is for admissions to B.Tech admissions, Paper 2 is for B.Arch programme’s . JEE Main exam pattern would give candidate’s an overview about the marking scheme and other related details about the exam.
JEE Main 2019 paper 1 will be held online (computer-based mode) while Paper 2 will be conducted partly online (mathematics and aptitude test) and partly offline (drawing test). In JEE Main, candidates will be required to answer questions from three subjects – Physics, Chemistry and Mathematics.
- JEE Main 2019 exam comprises two sections – Paper 1 and Paper 2. Both the sections are three hours long.
- Paper 1 for candidates seeking admissions to B.Tech programmes at IITs, NITs, IIITs and CFTIs.
- JEE Main Paper 2 is for aspirants seeking admissions to B.Arch programmes at NITs, IIITs and CFTIs.
- JEE Main Paper 1 will be held completely online while Paper 2 will be held in online as well as offline mode.
- The medium for both papers will be English, Hindi and Gujarati.
Take a look at JEE Main exam pattern 2019, marking scheme and other related details below :
| Particulars | Paper 1 | Paper 2 |
| Exam mode | Online (Computer based) | Online (Mathematics and Aptitude) and offline (Drawing test) |
| Number of sections and subjects | 3 (Physics, Chemistry and Mathematics) | 3 (Drawing, Mathematics and Aptitude) |
| Duration of exam | 3 hours (180 minutes); 60 minutes per section | 3 hours (180 minutes); 60 minutes per section |
| Number of questions | 90 (30 questions per section) | Paper 2: 82 questions (Mathematics: 30 questions, Aptitude: 50 and Drawing: 2) |
| Type of questions | MCQs; 4 options with only 1 correct option | Mathematics and Aptitude: Objective type questionsDrawing: Questions to test the candidate’s drawing and sketching skills |
| JEE Main Total Marks | 360 marks | 390 marks (Drawing section will be of total 70 marks, marking of every question will be given along with it) |
| Language of paper | English, Hindi and Gujarati (Aspirant’s from Gujarat, Daman & Diu and Dadra and Nagar Haveli can opt for Gujarati as well) | English, Hindi and Gujarati (Aspirant’s from Gujarat, Daman & Diu and Dadra and Nagar Haveli can opt for Gujarati as well) |
| JEE Main Marking scheme | +4 marks for correct answer; -1 mark for incorrect answer; 0 marks for un-attempted questions |
+4 marks for correct answer; -1 mark for incorrect answer; 0 marks for un-attempted questions |
JEE Main Marking Scheme :
The table given below provides a brief of the marking scheme, expected to be followed for JEE Main 2019
| Particulars | Paper 1 | Paper 2 |
| Correct Answer | +4 | +4 |
| Incorrect Answer | -1 | -1 |
| Un-attempted Question | 0 | 0 |
| Marks per section | 30 questions X 4 marks = 120 marks per section | Mathematics: 30 questions X 4 marks = 120 marks |
| Aptitude Test = 50 questions X 4 marks = 200 marks | ||
| Drawing test = 2 questions X 35 marks = 70 marks | ||
| Total marks | 360 marks | 390 marks |
Method To Determine JEE Main Merit List 2019
| Paper 1 | Paper 2 |
| Conversion of raw score in Mathematics, Physics, Chemistry and Total into NTA scores. | Merit list for JEE Main Paper 2 will be based on the total marks secured by the candidate. |
| Overall merit shall be prepared by merging NTA scores of each shift [First & Second shift] and all days |
Method Of Resolving Ties In JEE Main 2019
Candidates obtaining equal Total NTA scores in Paper-1 and Paper 2, in following descending order:
| Paper 1 | Paper 2 |
| NTA score in MathematicsNTA score in PhysicsNTA score in Chemistry
Candidates older in Age |
Marks obtained in Aptitude TestMarks obtained in Drawing Test Candidates older in age |
If the resolution is not possible after this criterion, candidates will be given same rank
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